Question

X-y+z=5
2y+3z=14
-3y+2z=5

Answer 1

question ?

Answer 2

How to find y and z ?

Answer 3

use elimination and subtitution method.
2st equation times 2, we get :
4y+6z=28

2rd equation times 3, we get :
-9y+6z=15

subtract both equations above :
4y+6z=28
-9y+6z=15
----------- -
13y = 13
divideb both sides by 13 we get
13y/13 = 13/13
y = 1

now subtitute y = 1 to one of equations above (let to 2nd eqution)
2y+3z=14
2(1) + 3z = 14
2 + 3z = 14
subtracted by 2 on both sides, we get
2 + 3z - 2 = 14 - 2
3z = 12
divided by 3 both sides, we get
3z/3 = 12/3
z = 4

Answer 4

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