Question

miguel invested $20000 in three different funds that paid 4%, 5%, 6% for the year. the total income for the year from the three funds was $1060. the income from the 6% fund was twice the income from the 5% fund. what amount was invested in each fund

Answer 1

set up equations:
a+b+c = 20,000
.04a +.05b +.06c = 1060
.06c = 2*.05b

solve using substitution