Find the square root of the sum of the squares of the roots of the following ( I started the problem):
(9x^2 - 4)^4 - 10(9x^2 - 4)^2 + 9 = 0
This is how far I got, 0 = y^4 - 10y^2 + 9 so (y^2 - 9)(y^2 - 1) simplified to (y + 3)(y - 3)(y +1)(y - 1) therefore y = 3 or y = 1 ... then I got stuck, help please!

Question

Find the square root of the sum of the squares of the roots of the following ( I started the problem): 
(9x^2 - 4)^4 - 10(9x^2 - 4)^2 + 9 = 0
This is how far I got, 0 = y^4 - 10y^2 + 9 so (y^2 - 9)(y^2 - 1) simplified to (y + 3)(y - 3)(y +1)(y - 1) therefore y = 3 or y = 1 ... then I got stuck, help please!

myininaya · Answer

You get 4 y's.

myininaya · Answer

And then remember your substitution from earlier y=9x^2-4