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Mathematics 20 Online
OpenStudy (anonymous):

Evaluate integral sin(x)/cos^2(x)

OpenStudy (anonymous):

answer that is given is secx+C but kinda confused how to get that

OpenStudy (raden):

sinx/cos^2x = sinx/cosx * 1/cosx = secxtanx obvious, the its integral given secx

OpenStudy (raden):

i mean : |dw:1383265660598:dw|

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