Question

Find the distance between point (-3,4) and (6,1) and please explain.

Answer 1

distance = sq rt (x2 - x1)^2 + (y2 - y1)^2
(-3,4) x1 = -3 and y1 = 4
(6,1) x2 = 6 and y2 = 1
now lets sub
d = sq rt (6 - (-3)^2 + (1 - 4)^2
d = sq rt (6 + 3)^2 + (-3)^2
d = sq rt (9^2) + (-3)^2
d = sq rt (81 + 9)
d = sq rt 90
d = 9.48