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\[g(x)=f(x-h)\] is a function shifted h units horizontally. if h is positive, then it's a shift to the right and if h is negative, it's a shift to the left. h = the value of x that makes (x-h) = 0
x+3 is the exponent so would the 3 shift 3 up?
no... let \[f(x) =4\left( 2 \right)^x\text{ then }g(x) = f(x+3)=4\left( 2 \right)^{x+3}\]
so since its in parentheses it wud shift 3 units down?
no, did you read what i wrote first?
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o ok it shifts to the right according to what you said right?
what is h?
positive 3
so 3 + 3 = 0?
o no its negative 3
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yeah
so what's the shift?
left 3?
yes, good!
ok than you
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you're welcome
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