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solve for x. 6-(2-3 cot x)= 5 cot x
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6-2+3cot x =5cot x 4=2cot x cot x = 2 tan x =1/2 \[x =\tan^{-1} \frac{1}{2}\]
oops, beat to the punch
didn't we need to factor ?? or no?
he factored the negative sign then added/subtracted
why should we need a factor..its not a quadratic equarion
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probably thought the 6 needed to be factored into ( )
or foiled rather
ok I got it thanks !!!
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