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the roots of the equation are(where a,b and c are rational numbers) a.both rational roots b.one rational and one irrational c.both irrational d.complex roots
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\[(a+2b-3c)^2+(b+2c-3a)x+c+2a-3b=0\]
@Mashy pls...hlp me in dis one /
do u know how to check the nature of the roots? in general for a quadratic equation?
yaa for sure by using discriminant
the answer to this question is a. but i m not able to get how
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actually i solved it and i get 2 values of x out of which one is positive and other is negative
\[25b^2+a^2+16c62+8ac-40bc-10ab\]
it's cuming out to be the discriminant
and sry for my mistake that was 16b^2
wait lemme check
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