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Mathematics 6 Online
OpenStudy (anonymous):

is anyone in Algebra 2a I need help

OpenStudy (solomonzelman):

Ask away! Shoot!

OpenStudy (anonymous):

I need help with Unit 3

OpenStudy (solomonzelman):

if you understand the directions, then we can help you!

OpenStudy (anonymous):

Whats the question?

OpenStudy (anonymous):

hold on pulling it up

OpenStudy (anonymous):

OpenStudy (anonymous):

@Easyaspi314

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (anonymous):

@huliebby

OpenStudy (anonymous):

|dw:1383285587781:dw|

OpenStudy (anonymous):

My graph is sloppy...but clearly has the point (5,0) which will maximize the 7x-3y.

OpenStudy (anonymous):

so 5,0 is the answer

OpenStudy (anonymous):

I graphed all the inequalities; shaded where appropriate; found convex points; max is at (5,0) for the condition.

OpenStudy (anonymous):

5,0 will maximize 7x-3y.

OpenStudy (anonymous):

Note that (5,0) is one of the vertices. I circled that in on the graph.

OpenStudy (anonymous):

I dont understand nun of this

OpenStudy (anonymous):

If I can graph all the inequalities clearer, I can explain better. What you need to do, is graph all 4 inequalities, then see where the lines meet, they are called vertices, and from the vertices find the max.

OpenStudy (anonymous):

Perhaps someone else can give a clear graph; I dont have the tools to give a clearer graph of all 4 inequalities.

OpenStudy (anonymous):

Sorry.

OpenStudy (anonymous):

Monster...cant you graph all 4 inequalities?

OpenStudy (anonymous):

im still lost im not good in all of this

OpenStudy (anonymous):

Sorry, I need graphing tools which I dont have available.

OpenStudy (anonymous):

What about the other guys you asked......maybe they can graph with a graphing tool.

OpenStudy (anonymous):

One thing is clear, the first 2 inequalities when graphed is only in the first quadrant. Thtas where x and y are both greater than or equal to 0.

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