plans for a stadium are drawn on a coordinate grid. one wall lies on the line y=2x+3. a perpendicular wall passes through the point (4, -7). write the equation of the line that contains the new wall
just gave you that link...
y=-1/2x-5 y=2x-15 y=1/2x-9 y=-2x+1
how do you find a perpendicular slope?
idk
im watching a khan academy video though maybe it could help
I can help explain this right now in a short simple phrase.
go on then
multiplicative inverse of the slope then times '-1' is your perpendicular slope.
@abbie, see? So what is the slope going to be?
for a slope a it is -1/a
ok
so if for A the slope is -1/A, for 2 the slope is _
um 1/2?
close, (it is multiplicative inverse, and then times -1)
-2?
you got the 1/2 part right, but think one more time....
-1/2
Yup! Bingo!
lol ok
K, so lets graph the line y=2x+3. Plug in -1 & 1 for x and connect the points that you get with a strait line.
|dw:1383375566126:dw|
now graph the same but add the point (4, -7) to the graph. (don't connect it to the line yet, just do the same graph as mine and draw this additional point.)
Im having a headache right now I think Ill do it later
|dw:1383375856706:dw| I graphed this on a paper.
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