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OpenStudy (anonymous):
help |5x + 5| < 10 A. x < –3 or x > 1 B. –3 < x < 1 C. x < –1 or x > 3 D. –1 < x < 3
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OpenStudy (anonymous):
b
OpenStudy (austinl):
@trumpetmaster7777 Please don't just give the answer.
OpenStudy (anonymous):
l 5(-3) +5 l <10 -15+5 -10 10 < 10
OpenStudy (anonymous):
thank you so much i needed that
OpenStudy (anonymous):
I'm trying to work it out give me time
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OpenStudy (austinl):
For this problem, you need to set it up as two individual inequalities. |5x + 5| < 10 (5x+5)<10 & -(5x+5)<10 Then you solve for x in both of them!
OpenStudy (anonymous):
5(1) +5 < 10 5+5 <10 10<10 so anywhere in bettween less than 1 and greater than -3
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