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OpenStudy (anonymous):
Hi all! How might I take invtan (x^2) ?
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OpenStudy (anonymous):
the answer is invtan (x^2)
OpenStudy (anonymous):
lol said that just for you @austinL
OpenStudy (anonymous):
Is it 1/(1+(x^2)^2) -> 1/(1+x^4) ?
OpenStudy (anonymous):
I'm just trying to figure out how to write the answer and how I'm supposed to find it
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