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Solve. 4(a + 2) = 14 – 2(3 – 2a) A. all real numbers B. –1 C. no solution D. –2
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4(a + 2) = 14 – 2(3 – 2a) expand '4(a+2) and '-2(3-2a)'
thanks
Tell me what you get.
b
no, that's ain't right.
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c
try to solve for a and tell me if you have any difficulties doing that.
don't guess, use logic.....
a
\[4(a + 2) = 14 – 2(3 – 2a)\]\[4a + 8 = 14 – 6 + 4a)\]\[4a+8=4a+8---> 4a=4a\]
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yes, it is a.
because no matter what you plug in for a, it will work, right?
?
don't get it?
it is a, and I just explained why.
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ohhh ok i get it
4a=4a, or a=a, whatever you plug in for a the equation will be true.
good!
(•‿•)
thx
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