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OpenStudy (anonymous):
Solve on the interval {0,2Pi} (cosx+1)(2cos^2 x -3cosx -2) = 0 x=pi x=pi/6 x=pi/3 x=5pi/4
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OpenStudy (amoodarya):
hint a= cos x (a+1)(2a^2-3a-2)=0
OpenStudy (amoodarya):
a=-1 a=(3+-root(9-4(2)(-2)))/4 so a=2, -1/2
OpenStudy (anonymous):
WHAT
OpenStudy (anonymous):
@amoodarya
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