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I'd presume Z is between the 2 sides |dw:1383331109269:dw| you'll need the law of cosines if its not a right triangle...
its not stated if its a right triangle or not, it just says x=3m y=5, Zangle= 50, find z?
am i correct to use c^2= a^2+b^2-2ab cos C here?
x=3 which would be a, y=5 which would be B, cos C= 50?
that will give you little z
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alright thought so thanks
|dw:1383363647100:dw|
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