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Which value for x makes the open sentence true? 5 + 4 • x = 32 + x2 A. 5 B. 3 C. 4 D. 2
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solve for x
\[5+4 \times x=32+x^2\] solve for x, do you know how?
bunki it should be c
\[5+4x-32-x^2=0\]rearrange\[-x^2+4x-27=0\]\[x^2-4x+27=0\]\[SOLVE!\]
thank you all c;
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I don't think it is c though it doesn't work if you plug it in.
\[(x-2)^2=-27+4\]\[x=2±isqrt{23}\]
\[x=2±i \sqrt{23}\]
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