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Which of the following is the solution set for the conjunction –6 < 4x + 2 < 6?
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-2<x<1
subtract 2 from each side of the less than symbols then divide both sides by 4
\(\bf -6 < 4x + 2 < 6\quad \textit{adding -2 to all sides}\\ \quad \\ -6 -2< 4x \cancel{+ 2-2} < 6-2\implies -8<4x<4\quad \textit{divide all sides by 4}\\ \quad \\ \cfrac{-\cancel{8}}{\cancel{4}}<\cfrac{\cancel{4}x}{\cancel{4}}<\cfrac{\cancel{4}}{\cancel{4}}\implies \square ?\)
ok thx
when youi have 3 sides, left, middle, right, you add/multiply/else to ALL sides simultaneously, just like you'd if you only had left and right side only
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