Question

The area of a rectangle is 21 ft^2 , and the length of the rectangle is 1ft less than twice the width. Find the dimensions of the rectangle.

Answer 1

Area = length * width = \(\bf 21 ft^2\)
w = width
l = length

length of the rectangle is 1ft less than twice the width
-1 2 * w

length = 2w -1

\(\bf Area = length \times width\implies 21 = l\times w\\ \quad \\
\implies 21 = (2w-1)\times w\)

Answer 2

solve for "w" to see what the width is
the length is 2w-1, so twice that much minus 1