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evaluate log2 4-log2 2
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logn a - logn b = logn (a/b) Use that relationship as a first step
\[\log _{n}a - \log _{n}b = \log _{n}\frac{ a }{ b }\]
What do you get when you apply that?
i don't even know how to do any of this
You don't see how your problem matches up to the equation I wrote? What will your log2 4-log2 2 equal...looking at that next to my equation?
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|dw:1383339390848:dw| What goes in the box?
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