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The equation of a circle is (x + 12)2 + (y + 16)2 = (r1)2, and the circle passes through the origin. The equation of the circle then changes to (x – 30)2 + (y – 16)2 = (r2)2, and the circle still passes through the origin. What are the values of r1 and r2?
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The circle passes through the origin means the point (0,0) is on the circle. Plug in (0,0) into each equation to find r.
the first set of equations or the second set?
It says they both pass through the origin.
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