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Find f(x) if f(2) = 2 and the tangent line at x has slope (x − 1)e^(x^2 − 2x)
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calculus 1 or 2?
f'(x) = (x-1)e^(x^2-2x) Integrate f'(x) to get g(x)= f(x) + k. Evaluate g(2) to obtain the value of k. f(x) = g(x) - k.
yep, lol just like that.
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