Question

I need help !

Sole the equation for the exact values using the square root principle.

(2x-1)²+4=0

Answer 1

Square root principle:
\[\sqrt{a^2} = a\]
So we can say:
\[(2x-1)^2+4=0\\(2x-1)^2=-4\\\sqrt{(2x-1)^2}=\sqrt{-4}\\2x-1=\sqrt{-4}\\2x=\sqrt{-4}+1\\x=\frac{\sqrt{-4}+1}{2}\]

Answer 2

thank you so much