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Mathematics 19 Online
OpenStudy (anonymous):

Find a vector equation of the line tangent to the graph of r(t) at the point Po on the curve. -> r(t)= 4costi - 3tj ; Po (2, -pi) -> r(t)= t^2i-(1/1+t)j+(4-t^2)k ; Po= (4,1,0)

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