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OpenStudy (anonymous):
Write the first trigonometric function in terms of the second for θ in the given quadrant. sec θ, sin θ; θ in Quadrant III
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OpenStudy (luigi0210):
Is there anymore info provided?
OpenStudy (anonymous):
Nope
OpenStudy (anonymous):
I know I have to use the pythagorean identites but I'm having trouble figuring out which one to use
OpenStudy (ddcamp):
Use sin² + cos² = 1: cos² = 1-sin² cos = sqrt(1-sin²) sec = 1/sqrt(1-sin²)
OpenStudy (anonymous):
sin is negative in Q3
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OpenStudy (anonymous):
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