Question

Anyone to help

Answer 1

Please do question 2

Answer 2

area of the section of circle minus the triangle. The triangle has
\[ \textrm{height} \ = r \cos (\theta/2) \]
\[ \textrm{base} \ = 2 \ r\sqrt{1-cos^2 (\theta/2)}\]

Shaded area
\[ (\pi r^2) \frac{129º}{360º} - r^2 \cos{\theta/2}\sqrt{1-cos^2 (\theta/2)}\]