Ask your own question, for FREE!
Mathematics 56 Online
jigglypuff314 (jigglypuff314):

If f(x) = cos(pix), find the value of the 13th derivative of f(x) at x = 2/3. is there a way to do this without taking the derivative of the derivative of the derivative of the derivative etc 13 times?

OpenStudy (anonymous):

No, but it's a pretty easy derivative to take cos(pix)--->-sin(pix)---->-cos(pix)--->sin(pix)----cos(pix)---> Notice it comes back to cos(pix) every 4th derivative and repeats the pattern.

jigglypuff314 (jigglypuff314):

yeah so I got to 13th which is -sin(pix) but how would I add in the chain rule?

OpenStudy (anonymous):

oops my bad, i messed up slightly

OpenStudy (anonymous):

cos(pix)--->-pi*sin(pix)---->-pi^2*cos(pix)--->pi^3*sin(pix)----pi^4cos(pix)---> fixed.

OpenStudy (anonymous):

you gotta keep increasing that pi term outside, 'cause you have to take the derivative of that pi*x each time, too

jigglypuff314 (jigglypuff314):

so it would be -pi^13*sin(pix) ?

OpenStudy (anonymous):

yes!

jigglypuff314 (jigglypuff314):

okay, thank you so much! :D

OpenStudy (anonymous):

no problem.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!