If f(x) = cos(pix), find the value of the 13th derivative of f(x) at x = 2/3. is there a way to do this without taking the derivative of the derivative of the derivative of the derivative etc 13 times?
No, but it's a pretty easy derivative to take cos(pix)--->-sin(pix)---->-cos(pix)--->sin(pix)----cos(pix)---> Notice it comes back to cos(pix) every 4th derivative and repeats the pattern.
yeah so I got to 13th which is -sin(pix) but how would I add in the chain rule?
oops my bad, i messed up slightly
cos(pix)--->-pi*sin(pix)---->-pi^2*cos(pix)--->pi^3*sin(pix)----pi^4cos(pix)---> fixed.
you gotta keep increasing that pi term outside, 'cause you have to take the derivative of that pi*x each time, too
so it would be -pi^13*sin(pix) ?
yes!
okay, thank you so much! :D
no problem.
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