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What are the x-intercepts for: y= sin πx + cos πx ???
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\(\bf y = sin(\pi x)+cos(\pi x)\implies 0= sin(\pi x)+cos(\pi x)\\ \quad \\ -sin(\pi x)=cos(\pi x)\implies sin(-\pi x)=cos(\pi x)\\ \quad \\ sin(-\pi x)=cos(-\pi x)\implies sin^2(-\pi x)=cos^2(-\pi x)\\ \quad \\ sin^2(-\pi x)-cos^2(-\pi x)=0\implies sin(-2\pi x) = 0\\ \quad \\ sin^{-1}(sin(-2\pi x)) = sin^{-1}(0)\implies -2\pi x= sin^{-1}(0)\)
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