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Is 100x^2-1 prime???
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are you trying to solve for x?
Factor completly
ax^2 +bx+c is prime only if b^2-4ac is not a perfect square so, find b^2-4ac for your question
Just yes or no would be fine
compare 100x^2-1 with ax^2+bx+c a=100. b=0, c=-1 then b^2-4ac = 0 - 4(100)(-1) =400 is 400 a perfect square ? just say yes or no, would be fine
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Yes 400 is a perfect square
b^2-4ac given a=100 , b=0 and c=-1 now put in it 0^2-4(100)(-1) 0+400=400 it is not prime no;
correct! then your quadratic expression is NOT prime
i'll cut to the chase without giving the answer: yes it can be factored.
any more doubts on this?
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How can it be factored then?
difference of squares
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