i chose c am i correct? 1. Which function is an odd function? (Points : 1) f(x) = 0.8x^3 f(x) = 5x^2 f(x) = 0.7x^2 + 3 f(x) = 3x - 1
@hartnn what do you think?
for an odd function f(-x) = -f(x)
so, just replace 'x' by -x in your functions, what do u get ?
f(x) = 0.8(-x)^3 f(-x) = (5-x)^2 f(-x) = 0.7(-x)^2 + 3 f(=x) = 3(-x) - 1
so whats (-x)^3= ... ?
-x *-x * -x = (+)x^3
2 negatives become positive but 3 negatives is negative only
but the exponent wouldn't it be -x multiplied by itself 3 times?
yes
-x *-x * -x = (-)x^3
but its separated like this?: (-x * -x) *-x
x^2*-x = -x^3
ok so , then my answer is b or c
no, you need the - for a, f(-x)=-f(x) so its odd
its odd if (-x) is not equal to f(x) or -f(x) right?
i have them mixed up
its odd if it is =-f(x)
so a = 0.8 * (-x) ^3 = -0.8 depending on what x is?
what!?
for it to be odd it has to = -f(x)
f(x) = 0.8x^3 is odd, because f(-x) = -f(x)
oh, so i really just had to focus on f(x) like the choices of a and b because i was only given f(-x) not in slope intercept form
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