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OpenStudy (notsmartatall):
if y varies directly as x and as the square of z, and y=25/9 when x=5 and z=1, find y when x=1 and z=4 a. y=(5/9)xz^2; y(1,4) = (80/9) b. y=(9/5)xz^3; y(1,4)=(1/8) c. y=(45/5)xz^2; y(1,4)=(80/9) d. y=(9/5)xz^2; y(1,4)=0
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OpenStudy (notsmartatall):
huh @ehuman lol i didnt get anything you just said haha
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