Question

if y varies directly as x and as the square of z, and y=25/9 when x=5 and z=1, find y when x=1 and z=4
a. y=(5/9)xz^2; y(1,4) = (80/9)
b. y=(9/5)xz^3; y(1,4)=(1/8)
c. y=(45/5)xz^2; y(1,4)=(80/9)
d. y=(9/5)xz^2; y(1,4)=0

Answer 1

huh @ehuman lol i didnt get anything you just said haha