Question

Af/ax. f(x,y)=( xy-1)^2

Answer 1

can u plz help mw with my question

Answer 2

af/ax?

Surely you mean
\[\Large \frac{\partial f}{\partial x}\] right? :D

Answer 3

Yes ;)

Answer 4

Well then, it's actually pretty easy.
Just differentiate \[\Large (xy^{-1})^2 = x^2y^{-2}\]with respect to x, and pretend y is just a constant.

Answer 5

=2x(xy-1) ?