Question

How to do this problem? http://i262.photobucket.com/albums/ii86/hollist2/mathhelpme_zps2fc473f6.jpg If you don't want to click the link the problem looks like. lim x -> -2 x^3 + 8 / x + 2 Thanks!

Answer 1

hint : x^3 + 8 = x^3 + 2^3

Answer 2

factor it using a^3 + b^3 formula

Answer 3

Here is some of my work. but i get stuck at this part: http://s262.photobucket.com/user/hollist2/media/mathhelpme2_zps009970ab.jpg.html

Answer 4

a^3 + b^3 = (a+b)(a^2-ab+b^2)

Answer 5

\(\huge \lim \limits_{x \to -2} \frac{ x^3 + 8 }{x+2}\)


\(\huge \lim \limits_{x \to -2} \frac{ x^3 + 2^3 }{x+2}\)

\(\huge \lim \limits_{x \to -2} \frac{ (x+2)(x^2-2x+4) }{x+2}\)

\(\huge \lim \limits_{x \to -2} ~~~x^2-2x+4\)

\(\huge (-2)^2-2(-2)+4\)

Answer 6

simplify

Answer 7

oh okay! I see now. Thank you!

Answer 8

np :)