Question

how do I find the limit of x approaching zero for (cosxsinx-x)/x^3

Answer 1

There are a couple of ways you can do this. Just start plugging in values of x near 0, like .1, then .01, .001, .000000001 and see what number you approach.

Another way might be to try taking the derivatives of the top and bottom separately, which is called L'Hopital's rule.

Answer 2

okay; thanks so much!