Let S = {−1, 0, 2, 4, 7}. Find f (S) if a) f (x) = 1. b) f (x) = 2x + 1. c) f (x) = x /5. d) f (x)=(x2 + 1)/3.
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btw the x/5 is a floor function
no wait ceiling...
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you would plot or you just need the results? or what is the question? :)
they dont ask for plot :) i think i got some of them but the C is a celinig function and the last is a floor function
those are the ones that i dont
get*
|dw:1383506625786:dw| this is not ceiling or floor function
no i mean i cant type it ... but its on my book
:) got it, so x/5 is taken as ceiling or floor, and which one, it matters.
X/5 it has ceiling function, the last one is floor
so we have x/5 ceiling means the smallest int not less than x (which is not x/5)
|dw:1383507080927:dw| something like this, would it be OK?
where did you stuck with the 4th?
uhm idnt need to plot, i need the values, so for S=-1 it turns into -1/5 but ... since it s celinig function .. what would the answer be?
I would not try to draw it :) but if we think together you can find out the results
so in 3rd the -1 goes -1/5 and ceiling is the largest int not greater than -1/5 which is that, integer, but not greater than -1/5?
that same value?
:) sorry I wrote wrong, ceiling is the smallest int not less than x :) the plot was good
-1 is int, but less than -1/5 so 0 is the good number.
you simply checks the two integers around it and you can find.
ohhhh it has to be integers right? ... good good. imma try to do it, thank you <3
yes, that is why the plot shows only horizontal lines. notice the blank circle and the full circle at the ends of the lines.
let's check the 4th one, with -1. (x2+1)/3
that has the floor, right?
yes, can i just ask you if my ansers r corret?
i have 0,0,1,1,2 as answers for each value of S
I do not know your answer. I think you will do it and if the logic is not good I may be able to fix it.
in case of the 4th function?
4th function is floor function. Are my answers right?
I do not think so 0,0,1 are OK, but how did you make the last two numbers? how did you calculate?
4/5 = 0.8 so it cant be 0 because is less than x aight?
x=4 x2=16 x2+1=17 (x2+1)/3=5,667 and ... 4th function and you seem to do the 3rd
im doing the third function still
those were my answers to the third function
ok, then I agree 0,0,1,1,2
for the 4th function i have 0,0,1,5,16, is that okay?
yes that is it, thank you.
omg thank you, u saved my life here, i can actually study for my test now :) thank yu thank you!
good luck
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