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OpenStudy (anonymous):
9x^(3/5)-5x^(6/5); c=0 Is a vertical cusp or vertical tangent. f'(x)= (27/(x^2)^(1/5))-6(x)^(1/5)
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OpenStudy (nincompoop):
your solution?
OpenStudy (anonymous):
I guessed both because theirs a point f'(x) is positive coming from the left but all the values before are negetive
OpenStudy (anonymous):
Im just not sure of it because of that
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