Question

The area of a rectangle is 77yd^2, and the length of the rectangle is10yd^2 less than three times the width. Find the dimensions of the rectangle.

Answer 1

anybody please help!!!!

Answer 2

@directrix

Answer 3

@mocham

Answer 4

@anybody

Answer 5

Assume Width = W
Length = (3*W - 10yd^2)

Area = L * W = W * (3*W - 10yd^2) = 77yd^2
Solve for W and then L.