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OpenStudy (anonymous):

I need help with this electric circuit problem please

OpenStudy (anonymous):

OpenStudy (anonymous):

I am not sure how to start to get the resistance

OpenStudy (anonymous):

I think it is safe to say that the voltage source, the resistor and the capacitance are on parallel? Therefore they would have the same voltage drop?

OpenStudy (anonymous):

I got it !!! :D First find the capacitance using the integral for voltage. Then use that capacitance to find the current through that branch using the current differential. Then do a KCL at a node to find the current through the resistor. Then r = v(t) / ir(t) , and find r at t=0 . AWESOME!

OpenStudy (theeric):

Wow, congrats! I didn't even think of integrals. I haven't gotten that in-depth into electronics.

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