integral of cos6x dx plz help!!
\[\frac{ \sin(6x) }{ 6 } + C\] because its derivative is cos(6x)
:O
how did u get that?? @Euler271
???? @zepdrix
what's the derivative of cos(6x)?
-sin6x ???? @Euler271
-6sin6x
the integral is the inverse operation of the derivative. so the integral of -6sin6x must be cos6x. tbh i dont even know how to explain it lol. i hope this helps
yea sorry!! I get u! thanks!@Euler271
^_^
That's a good method to get comfortable with, just sort of like.. advanced guessing. You know that the derivative will produce an extra factor of 6 because of the 6x inside of the trig function. So when we integrate, we need to divide by a factor of 6. If this is still confusing though, you can certainly perform a u-substitution:\[\Large \int\limits \cos6x\;dx,\qquad\qquad u=6x\]
Join our real-time social learning platform and learn together with your friends!