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Can somebody help me with this problem: If y^3=25x^2, determine dx/dt when x=5 and dy/dt=-2
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Implicit differentiation: 3y^2 dy/dt = 50x dx/dt Now plug in........
3y^2(-2)=50(-5)dx/dt
We don't know 'y'
You are right...but you do know that x = 5, so substitute x = 5 into the original equation, and solve for y (that's part of the problem).
ah!
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you get y^3 = 625 y = cube root of 625 or (625)^(1/3)
Now, you can easily finish to find dx/dt
Thanks for the help.
welcome.
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