Question

Write the equation of the line that is perpendicular to the line y = three halvesx + 4 and passes through the point (-6, 3).

y = three halvesx - 1

y = three halvesx + 3

y = -two thirdsx - 1

y = -two thirdsx + 3

Answer 1

your answer is y= -2/3x -1

Answer 2

would you like the algebra..

Answer 3

yes plz

Answer 4

y= 3/2x +4
the negative reciprocal is the perpendicular slope, which is -2/3. The line slope intercept form is y-y1=m(x-x1) so you plug in the points into the x, y, including the negative reciprocal slope.

y-3=-2/3(x-(-6))
y-3=-2/3(x+6)
y-3=-2/3x -4
+3 +3
y= -2/3x-1