Question

How do you find the expanded form of a binomial?
Such as: (5x+9)^2

Answer 1

(5x+9)*(5x+9)=(5x+9)*5x+9*(5x+9)=25x^2+45x+45x+81=25x^2+90x+81

Answer 2

"how" do you find it

Answer 3

(5x+ 9)^2

(5x + 9)(5x + 9)
use the FOIL method : First, outside, inside, last
First : multiply the first terms in each set...
5x * 5x = 25x^2
Outside : multiply the outside terms in each set...
5x * 9 = 45x
Inside : multiply the inside terms in each set..
9 * 5x = 45x
Last : multiply the last terms in each set ..
9 * 9 = 81
so now we have : 25x^2 + 45x + 45x + 81
combine like terms and you get : 25x^2 + 90x + 81

Answer 4

does that help ?

Answer 5

yes! thank you soooo much! :)

Answer 6

no problem :)