Question

The sum of two consecutive odd intergers is 236. What is the smallest interger?
a. 115
b. 117
c. 119
d. 113

Answer 1

x = 1st odd integer
x + 2 = 2nd odd integer

(x) + (x + 2) = 236 -- combine like terms
2x + 2 = 236 -- subtract 2 from both sides
2x = 236 - 2
2x = 234 -- divide by 2 on both sides
x = 117

x + 2 = 117 + 2 = 119

your 2 integers are 117 and 119, with 117 being the smallest integer.

Answer 2

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Answer 3

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Answer 4

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Answer 5

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