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Physics 7 Online
OpenStudy (anonymous):

The table lists the values for two parameters, x and y, of an experiment. What is the approximate value of y for x = 4.0?

OpenStudy (anonymous):

the table is x=2.5 y=6.25 x=9.4 y=88.36 x=15.6 y=243.36

OpenStudy (anonymous):

The table shows the relationship y = x^2. Therefore when x = 4.0, y = 16.0.

OpenStudy (anonymous):

do u understand?

OpenStudy (anonymous):

There is not an answer with 16.0. The answers i have are 11.0 17.85 24.10 and 43.20

OpenStudy (anonymous):

I thought it was 43.20 because because I halved 88.36 and that was the closest to it. I did that because 4.0*2 would be 8 and that is close to 9.4.

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