Question

2sin^2 x=sin x

Answer 1

you want this simplified?

Answer 2

need all real solution

Answer 3

for x?

Answer 4

I have pi/6, 0, and 5pi/6 need to know how to get pi. i have the answers, i just don't know how to get pi

Answer 5

1. subtract sinx from both sides.
2. factor out sinx
3. set each factor equal to 0
4. Solve each equation.

Answer 6

Note that, you need to take care about the general solution. like x = n \(\pi\) for sin x = 0

Answer 7

my answer key is saying that pi is an answer, i don't know how to solve for it

Answer 8

all real answers between [0, 2pi]

Answer 9

\[2\sin ^2x-\sin x=0\]
\[\sin x(2sin x-1)=0\]
\[\sin x=0\]
\[x=0,\pi \]
\[2\sin x-1=0\]
\[\sin x=\frac{1}{2}\]
\[x=\frac{\pi}{6},\frac{5\pi}{6}\]

Answer 10

The above answer by mertsj can be further corrected to :

x = n\(\pi\)
x = \(2n\pi + \cfrac{\pi}{6} \)
\(x = 2n\pi + \cfrac{5\pi}{6}\)

Answer 11

gotcha 0+180 makes sense now!

Answer 12

@mathslover Not for solutions between 0 and 2 pi

Answer 13

Oh! Thannks for correcting me Mertsj