Question

cos^2 x csc x - csc x =-sin x

Answer 1

you want to establish the identity?

Answer 2

\[\huge \cos^2x cscx - cscx = -sinx\]
>I like to change everything to sin and cos...
\[\huge (1 - sin^2x) \frac{1}{sinx} - \frac{1}{sinx} = -sinx\]
\[\huge \frac{1 - sin^2x}{sinx} - \frac{1}{sinx} = -sinx\]
\[\huge \frac{1 - sin^2x - 1}{sinx} = -sinx\]
\[\huge \frac{- sin^2x }{sinx} = -sinx\]
\[\huge - sinx = -sinx\]

Works out!

Answer 3

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