Question

f(x) = x^3+x^2-4x-4 a. The function’s end behavior
b. The x-intercept(s). Make sure to clearly state whether the graph crosses the x-axis OR touches the x-axis and turns around at each intercept
c. The y-intercept
d. Does the graph have y-axis symmetry, origin symmetry, or neither? Make sure to explain.

I got:
a. The graph falls to the left and rises to the right
b. x-intercepts are {-2,-1,2} At -1 the graph crosses the x-axis and at 2,-2 the graph touches the x-axis and turns around at each intercept.
c. The y-intercept is -4.
d. The graph has neither a y-axis or origin symmet

Answer 1

The graph crosses the x axis at each intercept.
http://www.wolframalpha.com/input/?i=f%28x%29+%3D+x^3%2Bx^2-4x-4

Answer 2

oh ok so it crosses at all three x intercept, does a, c, and d look correct....thanks for your help

Answer 3

yes

Answer 4

great thanks

Answer 5

yw