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(6/x+1-1/x)/(2/x-4/x+1)
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just to make sure, is it going to be \[\frac{ 6 }{ x+1 }-\frac{ 1 }{ x } / \frac{ 2 }{ x-4 } * \frac{ 1 }{ x+1 }\] ?
and if i interpreted right, then here's the step
\[\frac{ 6x-(x+1) }{ (x+1)x } / \frac{ 2 }{ (x-4)(x+1) }\]
\[\frac{ 5x-1 }{ (x+1)x } * \frac{ (x-4)(x+1) }{ 2 }\]
\[\frac{ (5x-1)(x-4) }{ 2x }\]
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