Ask
your own question, for FREE!
Mathematics
9 Online
Factor the polynomial completely using any method: -4w^8-8w^6+4x^4+8w^2
Still Need Help?
Join the QuestionCove community and study together with friends!
im assuming 4x^4 is 4w^4. you take out -4w^2 -4w^2(w^6+2w^4-w^2-2)
Assuming the given polynomial is \(-4w^8 - 8w^6 + 4w^4 + 8w^2\)
(-4w^4-8w^2)(w^4-1)
-4w^2(w^2+2)(x+1)(x-1)(x^2+1)
I think you accidentally mixed \(x's\) with \(w's\)
Still Need Help?
Join the QuestionCove community and study together with friends!
oops yeah used to using x
Thanks guys I missed this in class the other day when I was out sick! And yeah I did accidentally put that x in there instead of w.
I made mistakes too
\(-4w^2(w^6 + 2w^4 -w^2 - 2)\) \(-4w^2(w^4(w^2 + 2)-1(w^2 + 2)\) \(-4w^2(w^2+2)(w^4 - 1)\) \(-4w^2(w^2 + 2)(w^2 + 1)(w^2 - 1)\) \(-4w^2(w^2 + 2)(w^2 + 1)(w + 1)(w - 1)\)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH:
Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
11 minutes ago
0 Replies
0 Medals
3 days ago
3 Replies
2 Medals
6 days ago
3 Replies
0 Medals
1 day ago
9 Replies
1 Medal
1 week ago
2 Replies
1 Medal