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simplify y=3sin(3pi*x+9) into y=asin[b(x+c)] form
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take 3pi as the common factor so the term c becomes 3/pi and b is 3pi a should be obvious
Okay but how could b be 3pi when I need to find the period. That would make it 2 over 3?
well the period is 3pi/2pi so the period is 3/2
period is 2pi/b
So therefor it would be 2/3. Okay, thanks for the answer.
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lol... oops... yes the period is 2/3
Its okay lol.
here is a graph just to check hope it helps
Thanks :)
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