Question

Write an equation of a line in slope intercept form that is parallel to y = 3x+6 and passes through the point (-10, 2.5) Whoever awnsers gets a medal :D

Answer 1

y = 3x + 6....the slope here is 3 and a parallel line will have the same slope.

Now we will use point slope formula :
y - y1 = m(x - x1)
slope(m) = 3
(-10, 2.5) x1 = -10 and y1 = 2.5
now sub
y - 2.5 = 3(x - (-10)
y - 2.5 = 3(x + 10)
y - 2.5 = 3x + 30
y = 3x + 30 + 2.5
y = 3x + 32.5 <--- your parallel line

Answer 2

Thanks again :D

Answer 3

no problem :)